The problem is from codeforces http://www.codeforces.com/problemset/problem/12/A
This is probably the easiest problem I’ve ever seen in codeforces…. no tricks, no math or algorithms. It is very straightforward.
The python solution is cooked in seconds. 🙂
r1 = raw_input()
r2 = raw_input()
r3 = raw_input()
def chk():
return (r1[0] == r3[2]) and (r1[1] == r3[1]) and (r1[2] == r3[0]) and (r2[0] == r2[2])
if chk():
print "YES"
else:
print "NO"
It is noted that in python the logic operations are similar to Pascal, which are English words ‘and‘, ‘or‘ … It is defined as such probably because of the easiness to understand, unlike the ‘&&’, ‘||’ in C-like languages.
–EOF (The Ultimate Computing & Technology Blog) —
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