E, base of the natural logarithm


tex_b0ae8ac94ba8dcb947494ecd8411ed90 E, base of the natural logarithm algorithms beginner brute force implementation math python tricks , the base of the natural logarithm (e.g. tex_1e834a4784d958242c84da9213d86769 E, base of the natural logarithm algorithms beginner brute force implementation math python tricks ) can be expressed as the following equation:

tex_5424f0bf14ebfbfc051e7296c145577c E, base of the natural logarithm algorithms beginner brute force implementation math python tricks

The Euler’s formula involves tex_b0ae8ac94ba8dcb947494ecd8411ed90 E, base of the natural logarithm algorithms beginner brute force implementation math python tricks , which is:

tex_aab25b6a1ba74cbb228ed7b93f0bddf6 E, base of the natural logarithm algorithms beginner brute force implementation math python tricks

The Euler’s Identity is the special case when tex_e8b4fd043e2972e5d165a5bc42ada72d E, base of the natural logarithm algorithms beginner brute force implementation math python tricks ,

tex_fd1526bbfa049b2bbf544d70aa3e0bf9 E, base of the natural logarithm algorithms beginner brute force implementation math python tricks

The tex_b0ae8ac94ba8dcb947494ecd8411ed90 E, base of the natural logarithm algorithms beginner brute force implementation math python tricks constant coincides in many interesting problems. For example, the average number to add random numbers (tex_0875d07748fbbbe4f4ac3e8f674017fa E, base of the natural logarithm algorithms beginner brute force implementation math python tricks ) in order to obtain a sum larger than one can be obtained by the following Python code by brute-force over a few iterations.

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#!/usr/bin/env python
from random import random, seed
from math import e
 
maxn = 100
seed()
s = 0
for i in range(maxn):
    ss = 0
    j = 0
    while ss < 1:
        j += 1
        ss += random()
    s += j
 
ee = s * 1.0 / maxn
print "%.6f" % ee
print e, abs(e - ee)
#!/usr/bin/env python
from random import random, seed
from math import e

maxn = 100
seed()
s = 0
for i in range(maxn):
    ss = 0
    j = 0
    while ss < 1:
        j += 1
        ss += random()
    s += j

ee = s * 1.0 / maxn
print "%.6f" % ee
print e, abs(e - ee)

The 100 iterations give us an approximate value of tex_b0ae8ac94ba8dcb947494ecd8411ed90 E, base of the natural logarithm algorithms beginner brute force implementation math python tricks , which is 2.75 (with error = 0.0317).

2.750000
2.71828182846 0.031718171541

If we increase the iterations to 1000000,

Surprisingly, the output is the following.

2.718216
2.71828182846 6.58284590451e-05

We can see that if we keep increasing the iterations, the absolute error to tex_b0ae8ac94ba8dcb947494ecd8411ed90 E, base of the natural logarithm algorithms beginner brute force implementation math python tricks will be improved. And if maxn reaches tex_5660ba3d9abce8f28252e1b7ac3608b6 E, base of the natural logarithm algorithms beginner brute force implementation math python tricks , the tex_f12ef661983f8a61f0edcac85366130f E, base of the natural logarithm algorithms beginner brute force implementation math python tricks will be equal to tex_b0ae8ac94ba8dcb947494ecd8411ed90 E, base of the natural logarithm algorithms beginner brute force implementation math python tricks . Anybody can explain this in mathematics?

See also: Simple and Efficient C Program to Compute the Mathematic Constant E (Euler’s number)

–EOF (The Ultimate Computing & Technology Blog) —

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