We can use the dd command to generate a file size of given bytes however the parameters are not straighforward.
The “if=” specifies the input data (usually from /dev/zero or /dev/random) – and “of=” specifies the output (the target file). The count and bs (blocksize) multipled together will be the final output size.
Hence, here is a bash script that wraps the feature:
1 2 3 4 5 6 7 8 9 | #!/bin/bash # name this mkfile.sh if [[ -z "$1" || -z "$2" ]]; then echo Usage: $0 bytes filepath exit 1 fi dd if=/dev/zero of=$2 count=1 bs=$1 |
#!/bin/bash # name this mkfile.sh if [[ -z "$1" || -z "$2" ]]; then echo Usage: $0 bytes filepath exit 1 fi dd if=/dev/zero of=$2 count=1 bs=$1
For example – to create a file size of 1KB simply do this:
1 | $ ./mkfile.sh 1024 1kb.bin |
$ ./mkfile.sh 1024 1kb.bin
That will produce this:
1+0 records in
1+0 records out
1024 bytes (1.0 kB, 1.0 KiB) copied, 0.000211357 s, 4.8 MB/s
1 2 | $ ls -lh 1kb.bin -rw-r--r-- 1 root root 1.0K May 19 19:50 1kb.bin |
$ ls -lh 1kb.bin -rw-r--r-- 1 root root 1.0K May 19 19:50 1kb.bin
–EOF (The Ultimate Computing & Technology Blog) —
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