Given a string s and an integer array indices of the same length. The string s will be shuffled such that the character at the ith position moves to indices[i] in the shuffled string. Return the shuffled string.
Example 1:
Input: s = “codeleet”, indices = [4,5,6,7,0,2,1,3]
Output: “leetcode”
Explanation: As shown, “codeleet” becomes “leetcode” after shuffling.Example 2:
Input: s = “abc”, indices = [0,1,2]
Output: “abc”
Explanation: After shuffling, each character remains in its position.Example 3:
Input: s = “aiohn”, indices = [3,1,4,2,0]
Output: “nihao”Example 4:
Input: s = “aaiougrt”, indices = [4,0,2,6,7,3,1,5]
Output: “arigatou”Example 5:
Input: s = “art”, indices = [1,0,2]
Output: “rat”Constraints:
s.length == indices.length == n
1 <= n <= 100
s contains only lower-case English letters.
0 <= indices[i] < n
All values of indices are unique (i.e. indices is a permutation of the integers from 0 to n – 1).Hints:
You can create an auxiliary string t of length n.
Assign t[indexes[i]] to s[i] for each i from 0 to n-1.
Shuffle String In Python3
In Python, we can use list(s) to convert a string into a Character array. Then by using enumerate, we can re-arrange/shuffle the characters according to the given indices. Finally, we can join the characters into a result string that is shuffled.
1 2 3 4 5 6 | class Solution: def restoreString(self, s: str, indices: List[int]) -> str: res = list(s) for i in enumerate(indices): res[i[1]] = s[i[0]] return ''.join(res) |
class Solution: def restoreString(self, s: str, indices: List[int]) -> str: res = list(s) for i in enumerate(indices): res[i[1]] = s[i[0]] return ''.join(res)
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