Algorithm to Shuffle String in Python3 According to Index


Given a string s and an integer array indices of the same length. The string s will be shuffled such that the character at the ith position moves to indices[i] in the shuffled string. Return the shuffled string.

string-shuffle Algorithm to Shuffle String in Python3 According to Index python string

string-shuffle

Example 1:
Input: s = “codeleet”, indices = [4,5,6,7,0,2,1,3]
Output: “leetcode”
Explanation: As shown, “codeleet” becomes “leetcode” after shuffling.

Example 2:
Input: s = “abc”, indices = [0,1,2]
Output: “abc”
Explanation: After shuffling, each character remains in its position.

Example 3:
Input: s = “aiohn”, indices = [3,1,4,2,0]
Output: “nihao”

Example 4:
Input: s = “aaiougrt”, indices = [4,0,2,6,7,3,1,5]
Output: “arigatou”

Example 5:
Input: s = “art”, indices = [1,0,2]
Output: “rat”

Constraints:
s.length == indices.length == n
1 <= n <= 100
s contains only lower-case English letters.
0 <= indices[i] < n
All values of indices are unique (i.e. indices is a permutation of the integers from 0 to n – 1).

Hints:
You can create an auxiliary string t of length n.
Assign t[indexes[i]] to s[i] for each i from 0 to n-1.

Shuffle String In Python3

In Python, we can use list(s) to convert a string into a Character array. Then by using enumerate, we can re-arrange/shuffle the characters according to the given indices. Finally, we can join the characters into a result string that is shuffled.

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class Solution:
    def restoreString(self, s: str, indices: List[int]) -> str:
        res = list(s)
        for i in enumerate(indices):
            res[i[1]] = s[i[0]]
        return ''.join(res)
class Solution:
    def restoreString(self, s: str, indices: List[int]) -> str:
        res = list(s)
        for i in enumerate(indices):
            res[i[1]] = s[i[0]]
        return ''.join(res)

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