python
In Python, we can check if an array or list contains duplicate items using the following one-liner function.
1 2 | def contain_duplicates(list): return len(set(list)) != len(list) |
def contain_duplicates(list):
return len(set(list)) != len(list)The idea is to convert the list/array to set, then we can use the len function to get the sizes of the set and the original list/array. If they are both equal, then the array or list does not contain any duplicate items.
1 2 3 4 5 6 7 8 | >>> contain_duplicates([1,2,3,4]) False >>> contain_duplicates([1,2,3,4,2]) True >>> contain_duplicates(["aa", "bb"]) False >>> contain_duplicates(["aa", "bb", "aa"]) True |
>>> contain_duplicates([1,2,3,4]) False >>> contain_duplicates([1,2,3,4,2]) True >>> contain_duplicates(["aa", "bb"]) False >>> contain_duplicates(["aa", "bb", "aa"]) True
Alternatively, you can use the following naive solution based on set.
1 2 3 4 5 6 7 | def contain_duplicates(list): data = set() for i in list: if i in data: return True data.add(i) return False |
def contain_duplicates(list):
data = set()
for i in list:
if i in data:
return True
data.add(i)
return False The time complexity is O(N) and the space requirement is O(N) as well given the size of the list is N.
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