Logic Tests Series (2) - DECR | Algorithms, Blockchain and Cloud

coding-skills

What you can do with this tiny programming language with only 4 instructions? Today, we are going to implement the DECR function which decrements the variable by one, for example, DECR(X) where X=5 will make X=4.

1
2
3

DECR(X) {
 
}

DECR(X) {

}

The only 4 instructions are: INCR, LOOP, ZERO and ASGN. And all variables hold non-negative integers. To make X decremented by 1, we can increment a temp variable by (X-1) times..

DECR(X) {
   ZERO(V1)
   LOOP(X) {
     ASGN(X, V1)
     INCR(V1)
  }
}

DECR(X) {
   ZERO(V1)
   LOOP(X) {
     ASGN(X, V1)
     INCR(V1)
  }
}

We translate this to C++, which might be a bit easy to understand.

void decr(unsigned int &x) {
   int v1 = 0;
   int xx = x;
   for (; x > 0; -- x) {
      xx = v1;
      v1 ++;
   }
   x = xx;
}

void decr(unsigned int &x) {
   int v1 = 0;
   int xx = x;
   for (; x > 0; -- x) {
      xx = v1;
      v1 ++;
   }
   x = xx;
}

If you change the value of the loop variable x, the loop iteration count may be altered. Therefore, we declare a temp variable xx and assign the xx to X after loop when it gets incremented (x-1) times.

You may also like: 逻辑测试系列之二 – DECR

–EOF (The Ultimate Computing & Technology Blog) —

GD Star Rating
loading...

277 words
Last Post: The experience of using Teamviewer on iPhone SE, connecting to desktop, and SSH to VPS, in order to make a Robot Python script up running.
Next Post: Applying Naive Bayes Algorithm in Rock-Scissor-Paper Game

The Permanent URL is: Logic Tests Series (2) – DECR