We can sort a list of given strings from stdin and output to stdout using the following GoLang:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 | package main import ( "fmt" "bufio" "os" "sort" "strings" ) func main() { reader := bufio.NewReader(os.Stdin) var data = []string{} for true { s, _ := reader.ReadString('\n') s = strings.Trim(s, "\n") if len(s) == 0 { break } data = append(data, s) } sort.Strings(data) for _, a := range data { fmt.Println(a) } } |
package main
import (
"fmt"
"bufio"
"os"
"sort"
"strings"
)
func main() {
reader := bufio.NewReader(os.Stdin)
var data = []string{}
for true {
s, _ := reader.ReadString('\n')
s = strings.Trim(s, "\n")
if len(s) == 0 {
break
}
data = append(data, s)
}
sort.Strings(data)
for _, a := range data {
fmt.Println(a)
}
}The list of string data is constructed from os.Stdin line by line. And we call sort.Strings to sort them alphabetically in ascending order. Then we iterate over the sorted list and print them out to standard output.
For example:
1 2 3 4 5 6 7 8 | $ go run sort.go aaa ccc bbb Ctrl + D aaa bbb ccc |
$ go run sort.go aaa ccc bbb Ctrl + D aaa bbb ccc
–EOF (The Ultimate Computing & Technology Blog) —
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