Given an integer n (in base 10) and a base k, return the sum of the digits of n after converting n from base 10 to base k. After converting, each digit should be interpreted as a base 10 number, and the sum should be returned in base 10.
Example 1:
Input: n = 34, k = 6
Output: 9
Explanation: 34 (base 10) expressed in base 6 is 54. 5 + 4 = 9.Example 2:
Input: n = 10, k = 10
Output: 1
Explanation: n is already in base 10. 1 + 0 = 1.Constraints:
1 <= n <= 100
2 <= k <= 10
C++ Sum Digits of Base K
As we are converting from decimal to base K, we know exactly each digit and we can just sum them up along the process.
1 2 3 4 5 6 7 8 9 10 11 | class Solution { public: int sumBase(int n, int k) { int ans = 0; while (n > 0) { ans += n % k; n /= k; } return ans; } }; |
class Solution {
public:
int sumBase(int n, int k) {
int ans = 0;
while (n > 0) {
ans += n % k;
n /= k;
}
return ans;
}
};Python3 Sum Digits of Base K
Python code of iterating converting to Base K and suming the digits up. The Time complexity is 
. The space complexity is O(1).
1 2 3 4 5 6 7 | class Solution: def sumBase(self, n: int, k: int) -> int: ans = 0 while n: ans += n % k n //= k return ans |
class Solution:
def sumBase(self, n: int, k: int) -> int:
ans = 0
while n:
ans += n % k
n //= k
return ansSee also: Teaching Kids Programming – Binary Search Algorithm to Compute the Logarithm Base Two Function
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